19=3(x-3)+4x

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Solution for 19=3(x-3)+4x equation: 



19=3(x-3)+4x

We move all terms to the left:

19-(3(x-3)+4x)=0



We calculate terms in parentheses: -(3(x-3)+4x), so:

3(x-3)+4x

We add all the numbers together, and all the variables

4x+3(x-3)

We multiply parentheses

4x+3x-9

We add all the numbers together, and all the variables

7x-9

Back to the equation:

-(7x-9)



We get rid of parentheses

-7x+9+19=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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