19=4(b-15)+3

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Solution for 19=4(b-15)+3 equation: 



19=4(b-15)+3

We move all terms to the left:

19-(4(b-15)+3)=0



We calculate terms in parentheses: -(4(b-15)+3), so:

4(b-15)+3

We multiply parentheses

4b-60+3

We add all the numbers together, and all the variables

4b-57

Back to the equation:

-(4b-57)



We get rid of parentheses

-4b+57+19=0

We add all the numbers together, and all the variables

-4b+76=0

We move all terms containing b to the left, all other terms to the right

-4b=-76

b=-76/-4

b=+19

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