19=4(k+3)+3

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Solution for 19=4(k+3)+3 equation: 



19=4(k+3)+3

We move all terms to the left:

19-(4(k+3)+3)=0



We calculate terms in parentheses: -(4(k+3)+3), so:

4(k+3)+3

We multiply parentheses

4k+12+3

We add all the numbers together, and all the variables

4k+15

Back to the equation:

-(4k+15)



We get rid of parentheses

-4k-15+19=0

We add all the numbers together, and all the variables

-4k+4=0

We move all terms containing k to the left, all other terms to the right

-4k=-4

k=-4/-4

k=1

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