19=4+(2/x)

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Solution for 19=4+(2/x) equation: 



19=4+(2/x)

We move all terms to the left:

19-(4+(2/x))=0



Domain of the equation: x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(4+(+2/x))+19=0

We multiply all the terms by the denominator


-(4+(+2+19*x))=0



We calculate terms in parentheses: -(4+(+2+19*x)), so:

4+(+2+19*x)

determiningTheFunctionDomain
(+2+19*x)+4

We add all the numbers together, and all the variables

(19x+2)+4

We get rid of parentheses

19x+2+4

We add all the numbers together, and all the variables

19x+6

Back to the equation:

-(19x+6)



We get rid of parentheses

-19x-6=0

We move all terms containing x to the left, all other terms to the right

-19x=6

x=6/-19

x=-6/19

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