19=9+5(b+3)

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Solution for 19=9+5(b+3) equation: 



19=9+5(b+3)

We move all terms to the left:

19-(9+5(b+3))=0



We calculate terms in parentheses: -(9+5(b+3)), so:

9+5(b+3)

determiningTheFunctionDomain
5(b+3)+9

We multiply parentheses

5b+15+9

We add all the numbers together, and all the variables

5b+24

Back to the equation:

-(5b+24)



We get rid of parentheses

-5b-24+19=0

We add all the numbers together, and all the variables

-5b-5=0

We move all terms containing b to the left, all other terms to the right

-5b=5

b=5/-5

b=-1

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