19=c+(+12)

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Solution for 19=c+(+12) equation: 



19=c+(+12)

We move all terms to the left:

19-(c+(+12))=0

We add all the numbers together, and all the variables

-(c+12)+19=0

We get rid of parentheses

-c-12+19=0

We add all the numbers together, and all the variables

-1c+7=0

We move all terms containing c to the left, all other terms to the right

-c=-7

c=-7/-1

c=+7

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