19A/5B=12C

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Solution for 19A/5B=12C equation: 


x in (-oo:+oo)

((19*A)/5)*B = 12*C // - 12*C

((19*A)/5)*B-(12*C) = 0

((19*A)/5)*B-12*C = 0

19/5*A*B-12*C = 0

x należy do R

x in (-oo:+oo)

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