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19n^2-79n+25=0
a = 19; b = -79; c = +25;
Δ = b2-4ac
Δ = -792-4·19·25
Δ = 4341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{4341}}{2*19}=\frac{79-\sqrt{4341}}{38} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{4341}}{2*19}=\frac{79+\sqrt{4341}}{38} $
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