19p-6(4p-8)=7(p-12)

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Solution for 19p-6(4p-8)=7(p-12) equation: 



19p-6(4p-8)=7(p-12)

We move all terms to the left:

19p-6(4p-8)-(7(p-12))=0

We multiply parentheses

19p-24p-(7(p-12))+48=0



We calculate terms in parentheses: -(7(p-12)), so:

7(p-12)

We multiply parentheses

7p-84

Back to the equation:

-(7p-84)



We add all the numbers together, and all the variables

-5p-(7p-84)+48=0

We get rid of parentheses

-5p-7p+84+48=0

We add all the numbers together, and all the variables

-12p+132=0

We move all terms containing p to the left, all other terms to the right

-12p=-132

p=-132/-12

p=+11

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