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19x+1-3x=12+3x+15
We move all terms to the left:
19x+1-3x-(12+3x+15)=0
We add all the numbers together, and all the variables
19x-3x-(3x+27)+1=0
We add all the numbers together, and all the variables
16x-(3x+27)+1=0
We get rid of parentheses
16x-3x-27+1=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2
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