19x+1=3(3x+1)+7x-3

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Solution for 19x+1=3(3x+1)+7x-3 equation:



19x+1=3(3x+1)+7x-3
We move all terms to the left:
19x+1-(3(3x+1)+7x-3)=0
We calculate terms in parentheses: -(3(3x+1)+7x-3), so:
3(3x+1)+7x-3
We add all the numbers together, and all the variables
7x+3(3x+1)-3
We multiply parentheses
7x+9x+3-3
We add all the numbers together, and all the variables
16x
Back to the equation:
-(16x)
We add all the numbers together, and all the variables
3x+1=0
We move all terms containing x to the left, all other terms to the right
3x=-1
x=-1/3
x=-1/3

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