19x+1=4(3x+1)+7x-3

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Solution for 19x+1=4(3x+1)+7x-3 equation: 



19x+1=4(3x+1)+7x-3

We move all terms to the left:

19x+1-(4(3x+1)+7x-3)=0



We calculate terms in parentheses: -(4(3x+1)+7x-3), so:

4(3x+1)+7x-3

We add all the numbers together, and all the variables

7x+4(3x+1)-3

We multiply parentheses

7x+12x+4-3

We add all the numbers together, and all the variables

19x+1

Back to the equation:

-(19x+1)



We get rid of parentheses

19x-19x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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