19x+3=41+6x

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Solution for 19x+3=41+6x equation: 



19x+3=41+6x

We move all terms to the left:

19x+3-(41+6x)=0

We add all the numbers together, and all the variables

19x-(6x+41)+3=0

We get rid of parentheses

19x-6x-41+3=0

We add all the numbers together, and all the variables

13x-38=0

We move all terms containing x to the left, all other terms to the right

13x=38

x=38/13

x=2+12/13

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