19x-(3x-4)=4(5x-1)

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Solution for 19x-(3x-4)=4(5x-1) equation: 



19x-(3x-4)=4(5x-1)

We move all terms to the left:

19x-(3x-4)-(4(5x-1))=0

We get rid of parentheses

19x-3x-(4(5x-1))+4=0



We calculate terms in parentheses: -(4(5x-1)), so:

4(5x-1)

We multiply parentheses

20x-4

Back to the equation:

-(20x-4)



We add all the numbers together, and all the variables

16x-(20x-4)+4=0

We get rid of parentheses

16x-20x+4+4=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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