19x-(51-24x)/3=-(6x-50)/2

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Solution for 19x-(51-24x)/3=-(6x-50)/2 equation: 



19x-(51-24x)/3=-(6x-50)/2

We move all terms to the left:

19x-(51-24x)/3-(-(6x-50)/2)=0

We add all the numbers together, and all the variables

19x-(-24x+51)/3-(-(6x-50)/2)=0

We calculate fractions


19x+24x/()+(-(-(6x-50)*3)/()=0



We calculate terms in parentheses: +(-(-(6x-50)*3)/(), so:

-(-(6x-50)*3)/(

We multiply all the terms by the denominator


-(-(6x-50)*3)



We calculate terms in parentheses: -(-(6x-50)*3), so:

-(6x-50)*3

We multiply parentheses

-18x+150

Back to the equation:

-(-18x+150)



We get rid of parentheses

18x-150

Back to the equation:

+(18x-150)



We get rid of parentheses

19x+24x/()+18x-150=0

We multiply all the terms by the denominator


19x*()+24x+18x*()-150*()=0

We add all the numbers together, and all the variables

24x+19x*()+18x*()=0

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