19x-12=3x+4(4x-3)

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Solution for 19x-12=3x+4(4x-3) equation: 



19x-12=3x+4(4x-3)

We move all terms to the left:

19x-12-(3x+4(4x-3))=0



We calculate terms in parentheses: -(3x+4(4x-3)), so:

3x+4(4x-3)

We multiply parentheses

3x+16x-12

We add all the numbers together, and all the variables

19x-12

Back to the equation:

-(19x-12)



We get rid of parentheses

19x-19x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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