19x-23=(4x-1)+(2x+29)

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Solution for 19x-23=(4x-1)+(2x+29) equation: 



19x-23=(4x-1)+(2x+29)

We move all terms to the left:

19x-23-((4x-1)+(2x+29))=0



We calculate terms in parentheses: -((4x-1)+(2x+29)), so:

(4x-1)+(2x+29)

We get rid of parentheses

4x+2x-1+29

We add all the numbers together, and all the variables

6x+28

Back to the equation:

-(6x+28)



We get rid of parentheses

19x-6x-28-23=0

We add all the numbers together, and all the variables

13x-51=0

We move all terms containing x to the left, all other terms to the right

13x=51

x=51/13

x=3+12/13

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