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19x^2+11x-15=0
a = 19; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·19·(-15)
Δ = 1261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1261}}{2*19}=\frac{-11-\sqrt{1261}}{38} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1261}}{2*19}=\frac{-11+\sqrt{1261}}{38} $
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