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19x^2-11x-1=0
a = 19; b = -11; c = -1;
Δ = b2-4ac
Δ = -112-4·19·(-1)
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{197}}{2*19}=\frac{11-\sqrt{197}}{38} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{197}}{2*19}=\frac{11+\sqrt{197}}{38} $
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