19x2-15x-12=0

Solution for 19x2-15x-12=0 equation:

19x^2-15x-12=0

a = 19; b = -15; c = -12;
Δ = b2-4ac
Δ = -152-4·19·(-12)
Δ = 1137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1137}}{2*19}=\frac{15-\sqrt{1137}}{38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1137}}{2*19}=\frac{15+\sqrt{1137}}{38}
$