19x2=7x

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Solution for 19x2=7x equation:



19x^2=7x
We move all terms to the left:
19x^2-(7x)=0
a = 19; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·19·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*19}=\frac{0}{38} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*19}=\frac{14}{38} =7/19 $

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