19x=(13(x+1))-1

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Solution for 19x=(13(x+1))-1 equation: 



19x=(13(x+1))-1

We move all terms to the left:

19x-((13(x+1))-1)=0



We calculate terms in parentheses: -((13(x+1))-1), so:

(13(x+1))-1



We calculate terms in parentheses: +(13(x+1)), so:

13(x+1)

We multiply parentheses

13x+13

Back to the equation:

+(13x+13)



We get rid of parentheses

13x+13-1

We add all the numbers together, and all the variables

13x+12

Back to the equation:

-(13x+12)



We get rid of parentheses

19x-13x-12=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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