19x=-3x(5x+2)

Solution for 19x=-3x(5x+2) equation:

19x=-3x(5x+2)

We move all terms to the left:

19x-(-3x(5x+2))=0


We calculate terms in parentheses: -(-3x(5x+2)), so:

-3x(5x+2)

We multiply parentheses

-15x^2-6x

Back to the equation:

-(-15x^2-6x)


We get rid of parentheses

15x^2+6x+19x=0

We add all the numbers together, and all the variables

15x^2+25x=0

a = 15; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·15·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*15}=\frac{-50}{30}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*15}=\frac{0}{30}
=0
$