19z+36=3z+68

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Solution for 19z+36=3z+68 equation: 



19z+36=3z+68

We move all terms to the left:

19z+36-(3z+68)=0

We get rid of parentheses

19z-3z-68+36=0

We add all the numbers together, and all the variables

16z-32=0

We move all terms containing z to the left, all other terms to the right

16z=32

z=32/16

z=2

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