19z-11=2(-z+5)

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Solution for 19z-11=2(-z+5) equation: 



19z-11=2(-z+5)

We move all terms to the left:

19z-11-(2(-z+5))=0

We add all the numbers together, and all the variables

19z-(2(-1z+5))-11=0



We calculate terms in parentheses: -(2(-1z+5)), so:

2(-1z+5)

We multiply parentheses

-2z+10

Back to the equation:

-(-2z+10)



We get rid of parentheses

19z+2z-10-11=0

We add all the numbers together, and all the variables

21z-21=0

We move all terms containing z to the left, all other terms to the right

21z=21

z=21/21

z=1

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