19z=3z+32

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Solution for 19z=3z+32 equation:



19z=3z+32
We move all terms to the left:
19z-(3z+32)=0
We get rid of parentheses
19z-3z-32=0
We add all the numbers together, and all the variables
16z-32=0
We move all terms containing z to the left, all other terms to the right
16z=32
z=32/16
z=2

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