1=((1)/(1-a))+((a)/(a-1))

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Solution for 1=((1)/(1-a))+((a)/(a-1)) equation: 


D( a )

a-1 = 0

1-a = 0

a-1 = 0

a-1 = 0

a-1 = 0 // + 1

a = 1

1-a = 0

1-a = 0

1-a = 0 // - 1

-a = -1 // * -1

a = 1

a in (-oo:1) U (1:+oo)

1 = 1/(1-a)+a/(a-1) // - 1/(1-a)+a/(a-1)

1-(1/(1-a))-(a/(a-1)) = 0

1-(1-a)^-1-(a/(a-1)) = 0

(-1*a)/(a-1)-1/(1-a)+1 = 0

(-1*(a-1))/((1-a)*(a-1))+(-1*a*(1-a))/((1-a)*(a-1))+(1*(1-a)*(a-1))/((1-a)*(a-1)) = 0

1*(1-a)*(a-1)-1*(a-1)-1*a*(1-a) = 0

a^2-a^2-2*a+2*a-1+1 = 0

0 = 0

0/((1-a)*(a-1)) = 0

0/((1-a)*(a-1)) = 0 // * (1-a)*(a-1)

0 = 0

a belongs to the empty set

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