1=(-1/3)x+1

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Solution for 1=(-1/3)x+1 equation: 



1=(-1/3)x+1

We move all terms to the left:

1-((-1/3)x+1)=0



Domain of the equation: 3)x+1)!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


-((-1+1*3)x+1)=0



We calculate terms in parentheses: -((-1+1*3)x+1), so:

(-1+1*3)x+1

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

-2x-1=0

We move all terms containing x to the left, all other terms to the right

-2x=1

x=1/-2

x=-1/2

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