1=(-16)/3y

Solution for 1=(-16)/3y equation:

1=(-16)/3y

We move all terms to the left:

1-((-16)/3y)=0


Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R


We multiply all the terms by the denominator


-((-16)+1*3y)=0


We calculate terms in parentheses: -((-16)+1*3y), so:

(-16)+1*3y

determiningTheFunctionDomain
1*3y+(-16)

We add all the numbers together, and all the variables

1*3y-16

Wy multiply elements

3y-16

Back to the equation:

-(3y-16)


We get rid of parentheses

-3y+16=0

We move all terms containing y to the left, all other terms to the right

-3y=-16

y=-16/-3

y=5+1/3