1=(1/2)(9x+2)

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Solution for 1=(1/2)(9x+2) equation:



1=(1/2)(9x+2)
We move all terms to the left:
1-((1/2)(9x+2))=0
Domain of the equation: 2)(9x+2))!=0
x∈R
We add all the numbers together, and all the variables
-((+1/2)(9x+2))+1=0
We multiply parentheses ..
-((+9x^2+1/2*2))+1=0
We multiply all the terms by the denominator
-((+9x^2+1+1*2*2))=0
We calculate terms in parentheses: -((+9x^2+1+1*2*2)), so:
(+9x^2+1+1*2*2)
We get rid of parentheses
9x^2+1+1*2*2
We add all the numbers together, and all the variables
9x^2+5
Back to the equation:
-(9x^2+5)
We get rid of parentheses
-9x^2-5=0
a = -9; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-9)·(-5)
Δ = -180
Delta is less than zero, so there is no solution for the equation

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