1=(1/2)(9x+2)

Solution for 1=(1/2)(9x+2) equation:

1=(1/2)(9x+2)

We move all terms to the left:

1-((1/2)(9x+2))=0


Domain of the equation: 2)(9x+2))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/2)(9x+2))+1=0

We multiply parentheses ..

-((+9x^2+1/2*2))+1=0

We multiply all the terms by the denominator


-((+9x^2+1+1*2*2))=0


We calculate terms in parentheses: -((+9x^2+1+1*2*2)), so:

(+9x^2+1+1*2*2)

We get rid of parentheses

9x^2+1+1*2*2

We add all the numbers together, and all the variables

9x^2+5

Back to the equation:

-(9x^2+5)


We get rid of parentheses

-9x^2-5=0

a = -9; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-9)·(-5)
Δ = -180
Delta is less than zero, so there is no solution for the equation