1=(15x-5)2=(10x+35)

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Solution for 1=(15x-5)2=(10x+35) equation: 



1=(15x-5)2=(10x+35)

We move all terms to the left:

1-((15x-5)2)=0



We calculate terms in parentheses: -((15x-5)2), so:

(15x-5)2

We multiply parentheses

30x-10

Back to the equation:

-(30x-10)



We get rid of parentheses

-30x+10+1=0

We add all the numbers together, and all the variables

-30x+11=0

We move all terms containing x to the left, all other terms to the right

-30x=-11

x=-11/-30

x=11/30

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