1=(3+2y)x/2y

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Solution for 1=(3+2y)x/2y equation: 


x in (-oo:+oo)

1 = y*((x*(2*y+3))/2) // - y*((x*(2*y+3))/2)

1-(y*((x*(2*y+3))/2)) = 0

(-1*x*y*(2*y+3))/2+1 = 0

(-1*x*y*(2*y+3))/2+(1*2)/2 = 0

1*2-1*x*y*(2*y+3) = 0

2-2*x*y^2-3*x*y = 0

2-2*x*y^2-3*x*y = 0

2-3*x*y = 0 // - 2

-3*x*y = -2 // : -3*y

x = -2/(-3*y)

x-2/3*y^-1 = 0

(x-2/3*y^-1)/2 = 0

(x-2/3*y^-1)/2 = 0 // * 2

x-2/3*y^-1 = 0

x-2/3*y^-1 = 0 // + -2/3*y^-1

x = -(-2/3*y^-1)

x = 2/3*y^-1

x = 2/3*y^-1

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