1=(3+p)/14

Solution for 1=(3+p)/14 equation:

1=(3+p)/14

We move all terms to the left:

1-((3+p)/14)=0

We add all the numbers together, and all the variables

-((p+3)/14)+1=0

We multiply all the terms by the denominator


-((p+3)+1*14)=0


We calculate terms in parentheses: -((p+3)+1*14), so:

(p+3)+1*14

We add all the numbers together, and all the variables

(p+3)+14

We get rid of parentheses

p+3+14

We add all the numbers together, and all the variables

p+17

Back to the equation:

-(p+17)


We get rid of parentheses

-p-17=0

We add all the numbers together, and all the variables

-1p-17=0

We move all terms containing p to the left, all other terms to the right

-p=17

p=17/-1

p=-17