1=(3+u)/3

Solution for 1=(3+u)/3 equation:

1=(3+u)/3

We move all terms to the left:

1-((3+u)/3)=0

We add all the numbers together, and all the variables

-((u+3)/3)+1=0

We multiply all the terms by the denominator


-((u+3)+1*3)=0


We calculate terms in parentheses: -((u+3)+1*3), so:

(u+3)+1*3

We add all the numbers together, and all the variables

(u+3)+3

We get rid of parentheses

u+3+3

We add all the numbers together, and all the variables

u+6

Back to the equation:

-(u+6)


We get rid of parentheses

-u-6=0

We add all the numbers together, and all the variables

-1u-6=0

We move all terms containing u to the left, all other terms to the right

-u=6

u=6/-1

u=-6