1=(9x+4)8=(7x+32

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Solution for 1=(9x+4)8=(7x+32 equation: 



1=(9x+4)8=(7x+32

We move all terms to the left:

1-((9x+4)8)=0



We calculate terms in parentheses: -((9x+4)8), so:

(9x+4)8

We multiply parentheses

72x+32

Back to the equation:

-(72x+32)



We get rid of parentheses

-72x-32+1=0

We add all the numbers together, and all the variables

-72x-31=0

We move all terms containing x to the left, all other terms to the right

-72x=31

x=31/-72

x=-31/72

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