1=(f/6)-3

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Solution for 1=(f/6)-3 equation:



1=(f/6)-3
We move all terms to the left:
1-((f/6)-3)=0
We add all the numbers together, and all the variables
-((+f/6)-3)+1=0
We multiply all the terms by the denominator
-((+f+1*6)-3)=0
We calculate terms in parentheses: -((+f+1*6)-3), so:
(+f+1*6)-3
We add all the numbers together, and all the variables
(f+6)-3
We get rid of parentheses
f+6-3
We add all the numbers together, and all the variables
f+3
Back to the equation:
-(f+3)
We get rid of parentheses
-f-3=0
We add all the numbers together, and all the variables
-1f-3=0
We move all terms containing f to the left, all other terms to the right
-f=3
f=3/-1
f=-3

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