1=(k-97)/3

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Solution for 1=(k-97)/3 equation:



1=(k-97)/3
We move all terms to the left:
1-((k-97)/3)=0
We multiply all the terms by the denominator
-((k-97)+1*3)=0
We calculate terms in parentheses: -((k-97)+1*3), so:
(k-97)+1*3
We add all the numbers together, and all the variables
(k-97)+3
We get rid of parentheses
k-97+3
We add all the numbers together, and all the variables
k-94
Back to the equation:
-(k-94)
We get rid of parentheses
-k+94=0
We add all the numbers together, and all the variables
-1k+94=0
We move all terms containing k to the left, all other terms to the right
-k=-94
k=-94/-1
k=+94

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