1=(n-7)/8

Solution for 1=(n-7)/8 equation:

1=(n-7)/8

We move all terms to the left:

1-((n-7)/8)=0

We multiply all the terms by the denominator


-((n-7)+1*8)=0


We calculate terms in parentheses: -((n-7)+1*8), so:

(n-7)+1*8

We add all the numbers together, and all the variables

(n-7)+8

We get rid of parentheses

n-7+8

We add all the numbers together, and all the variables

n+1

Back to the equation:

-(n+1)


We get rid of parentheses

-n-1=0

We add all the numbers together, and all the variables

-1n-1=0

We move all terms containing n to the left, all other terms to the right

-n=1

n=1/-1

n=-1