1=(x-3)*(6x+5)-(3x+2)*(2x-1)

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Solution for 1=(x-3)*(6x+5)-(3x+2)*(2x-1) equation: 



1=(x-3)(6x+5)-(3x+2)(2x-1)

We move all terms to the left:

1-((x-3)(6x+5)-(3x+2)(2x-1))=0

We multiply parentheses ..

-((+6x^2+5x-18x-15)-(3x+2)(2x-1))+1=0



We calculate terms in parentheses: -((+6x^2+5x-18x-15)-(3x+2)(2x-1)), so:

(+6x^2+5x-18x-15)-(3x+2)(2x-1)

We get rid of parentheses

6x^2+5x-18x-(3x+2)(2x-1)-15

We multiply parentheses ..

6x^2-(+6x^2-3x+4x-2)+5x-18x-15

We add all the numbers together, and all the variables

6x^2-(+6x^2-3x+4x-2)-13x-15

We get rid of parentheses

6x^2-6x^2+3x-4x-13x+2-15

We add all the numbers together, and all the variables

-14x-13

Back to the equation:

-(-14x-13)



We get rid of parentheses

14x+13+1=0

We add all the numbers together, and all the variables

14x+14=0

We move all terms containing x to the left, all other terms to the right

14x=-14

x=-14/14

x=-1

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