1=(x/(x+1))-(3(x+2))

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Solution for 1=(x/(x+1))-(3(x+2)) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

1 = x/(x+1)-(3*(x+2)) // - x/(x+1)-(3*(x+2))

3*(x+2)-(x/(x+1))+1 = 0

(-1*x)/(x+1)+3*(x+2)+1 = 0

(-1*x)/(x+1)+(3*(x+2)*(x+1))/(x+1)+(1*(x+1))/(x+1) = 0

3*(x+2)*(x+1)+1*(x+1)-1*x = 0

3*x^2+8*x+x+1+6 = 0

3*x^2+9*x+7 = 0

3*x^2+9*x+7 = 0

3*x^2+9*x+7 = 0

DELTA = 9^2-(3*4*7)

DELTA = -3

DELTA < 0

1 = 0

1/(x+1) = 0

1/(x+1) = 0 // * x+1

1 = 0

x belongs to the empty set

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