1=(z+2)/3

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Solution for 1=(z+2)/3 equation: 



1=(z+2)/3

We move all terms to the left:

1-((z+2)/3)=0

We multiply all the terms by the denominator


-((z+2)+1*3)=0



We calculate terms in parentheses: -((z+2)+1*3), so:

(z+2)+1*3

We add all the numbers together, and all the variables

(z+2)+3

We get rid of parentheses

z+2+3

We add all the numbers together, and all the variables

z+5

Back to the equation:

-(z+5)



We get rid of parentheses

-z-5=0

We add all the numbers together, and all the variables

-1z-5=0

We move all terms containing z to the left, all other terms to the right

-z=5

z=5/-1

z=-5

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