1=-(a-5)+2a

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Solution for 1=-(a-5)+2a equation: 



1=-(a-5)+2a

We move all terms to the left:

1-(-(a-5)+2a)=0



We calculate terms in parentheses: -(-(a-5)+2a), so:

-(a-5)+2a

We add all the numbers together, and all the variables

2a-(a-5)

We get rid of parentheses

2a-a+5

We add all the numbers together, and all the variables

a+5

Back to the equation:

-(a+5)



We get rid of parentheses

-a-5+1=0

We add all the numbers together, and all the variables

-1a-4=0

We move all terms containing a to the left, all other terms to the right

-a=4

a=4/-1

a=-4

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