1=-2/3(5)+b

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Solution for 1=-2/3(5)+b equation:



1=-2/3(5)+b
We move all terms to the left:
1-(-2/3(5)+b)=0
Domain of the equation: 35+b)!=0
We move all terms containing b to the left, all other terms to the right
b)!=-35
b!=-35/1
b!=-35
b∈R
We add all the numbers together, and all the variables
-(+b-2/35)+1=0
We get rid of parentheses
-b+1+2/35=0
We multiply all the terms by the denominator
-b*35+2+1*35=0
We add all the numbers together, and all the variables
-b*35+37=0
Wy multiply elements
-35b+37=0
We move all terms containing b to the left, all other terms to the right
-35b=-37
b=-37/-35
b=1+2/35

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