1=-2/8(-3)+b

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Solution for 1=-2/8(-3)+b equation: 



1=-2/8(-3)+b

We move all terms to the left:

1-(-2/8(-3)+b)=0



Domain of the equation: 8(-3)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-2+1*8(-3)+b)=0



We calculate terms in parentheses: -(-2+1*8(-3)+b), so:

-2+1*8(-3)+b

determiningTheFunctionDomain
b-2+1*8(-3)

We add all the numbers together, and all the variables

b-26

Back to the equation:

-(b-26)



We get rid of parentheses

-b+26=0

We add all the numbers together, and all the variables

-1b+26=0

We move all terms containing b to the left, all other terms to the right

-b=-26

b=-26/-1

b=+26

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