1=-3(5r-3)+8(2r-1)

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Solution for 1=-3(5r-3)+8(2r-1) equation:



1=-3(5r-3)+8(2r-1)
We move all terms to the left:
1-(-3(5r-3)+8(2r-1))=0
We calculate terms in parentheses: -(-3(5r-3)+8(2r-1)), so:
-3(5r-3)+8(2r-1)
We multiply parentheses
-15r+16r+9-8
We add all the numbers together, and all the variables
r+1
Back to the equation:
-(r+1)
We get rid of parentheses
-r-1+1=0
We add all the numbers together, and all the variables
-r=0
r=0/-1
r=0

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