1=-3(k+2)+7

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Solution for 1=-3(k+2)+7 equation: 



1=-3(k+2)+7

We move all terms to the left:

1-(-3(k+2)+7)=0



We calculate terms in parentheses: -(-3(k+2)+7), so:

-3(k+2)+7

We multiply parentheses

-3k-6+7

We add all the numbers together, and all the variables

-3k+1

Back to the equation:

-(-3k+1)



We get rid of parentheses

3k-1+1=0

We add all the numbers together, and all the variables

3k=0

k=0/3

k=0

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