1=-4n+3(6+2n)-19

Solution for 1=-4n+3(6+2n)-19 equation:

1=-4n+3(6+2n)-19

We move all terms to the left:

1-(-4n+3(6+2n)-19)=0

We add all the numbers together, and all the variables

-(-4n+3(2n+6)-19)+1=0


We calculate terms in parentheses: -(-4n+3(2n+6)-19), so:

-4n+3(2n+6)-19

We multiply parentheses

-4n+6n+18-19

We add all the numbers together, and all the variables

2n-1

Back to the equation:

-(2n-1)


We get rid of parentheses

-2n+1+1=0

We add all the numbers together, and all the variables

-2n+2=0

We move all terms containing n to the left, all other terms to the right

-2n=-2

n=-2/-2

n=1