1=-6(-x/2-5)-(x+3

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Solution for 1=-6(-x/2-5)-(x+3 equation: 



1=-6(-x/2-5)-(x+3

We move all terms to the left:

1-(-6(-x/2-5)-(x+3)=0



Domain of the equation: 2-5)-(x+3)+1!=0

We move all terms containing x to the left, all other terms to the right

-5)-(x+3)+1!=-2

x∈R



We multiply all the terms by the denominator


-(-6(-x=0

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