1=-6(-x/2-5)-(x+3

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Solution for 1=-6(-x/2-5)-(x+3 equation:



1=-6(-x/2-5)-(x+3
We move all terms to the left:
1-(-6(-x/2-5)-(x+3)=0
Domain of the equation: 2-5)-(x+3)+1!=0
We move all terms containing x to the left, all other terms to the right
-5)-(x+3)+1!=-2
x∈R
We multiply all the terms by the denominator
-(-6(-x=0

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