1=-7(1-8x)+8(1+3x)

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Solution for 1=-7(1-8x)+8(1+3x) equation: 



1=-7(1-8x)+8(1+3x)

We move all terms to the left:

1-(-7(1-8x)+8(1+3x))=0

We add all the numbers together, and all the variables

-(-7(-8x+1)+8(3x+1))+1=0



We calculate terms in parentheses: -(-7(-8x+1)+8(3x+1)), so:

-7(-8x+1)+8(3x+1)

We multiply parentheses

56x+24x-7+8

We add all the numbers together, and all the variables

80x+1

Back to the equation:

-(80x+1)



We get rid of parentheses

-80x-1+1=0

We add all the numbers together, and all the variables

-80x=0

x=0/-80

x=0

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