1=-8+(x/2)

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Solution for 1=-8+(x/2) equation: 



1=-8+(x/2)

We move all terms to the left:

1-(-8+(x/2))=0

We add all the numbers together, and all the variables

-(-8+(+x/2))+1=0

We multiply all the terms by the denominator


-(-8+(+x+1*2))=0



We calculate terms in parentheses: -(-8+(+x+1*2)), so:

-8+(+x+1*2)

determiningTheFunctionDomain
(+x+1*2)-8

We add all the numbers together, and all the variables

(x+2)-8

We get rid of parentheses

x+2-8

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We get rid of parentheses

-x+6=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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